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Q7:
Find the sum of first 22 terms of an AP in which $d = 7$ and 22nd term is 149.

Solution :

Given:

An Arithmetic Progression (AP) where:

  • The common difference, $d = 7$
  • The number of terms, $n = 22$
  • The 22nd term, $a_{22} = 149$

To find:

The sum of the first 22 terms of the AP, denoted as $S_{22}$.

Step 1: Determine the first term ($a$) of the AP.

We use the general formula for the $n$-th term of an AP:

$a_n = a + (n - 1)d$

Substituting the given values ($n = 22$, $a_{22} = 149$, $d = 7$):

$149 = a + (22 - 1) \times 7$

$149 = a + (21) \times 7$

$149 = a + 147$

Subtracting 147 from both sides to isolate $a$:

$a = 149 - 147$

$a = 2$

Step 2: Calculate the sum of the first 22 terms ($S_{22}$).

We use the formula for the sum of the first $n$ terms of an AP when the last term ($l = a_n$) is known:

$S_n = \frac{n}{2} (a + a_n)$

Here, $n = 22$, $a = 2$, and $a_n = a_{22} = 149$.

Substituting these values into the formula:

$S_{22} = \frac{22}{2} (2 + 149)$

$S_{22} = 11 \times (151)$

Step 3: Perform the final multiplication.

$S_{22} = 11 \times 151$

$S_{22} = 1661$

Final Answer: The sum of the first 22 terms of the AP is 1661.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


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