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Q3(i):
In an AP: (i) given $a = 5, d = 3, a_n = 50$, find $n$ and $S_n$.

Solution :

Given:

The first term of the Arithmetic Progression (AP), $a = 5$.

The common difference of the AP, $d = 3$.

The $n^{th}$ term of the AP, $a_n = 50$.

To Find:

The number of terms, $n$, and the sum of the first $n$ terms, $S_n$.

Step 1: Finding the value of $n$

We use the standard formula for the $n^{th}$ term of an Arithmetic Progression:

$a_n = a + (n - 1)d$

[Where $a_n$ is the $n^{th}$ term, $a$ is the first term, $n$ is the number of terms, and $d$ is the common difference.]

Substituting the given values into the formula:

$50 = 5 + (n - 1)3$

Subtract 5 from both sides of the equation:

$50 - 5 = (n - 1)3$

$45 = (n - 1)3$

Divide both sides by 3:

$\frac{45}{3} = n - 1$

$15 = n - 1$

Add 1 to both sides to solve for $n$:

$n = 15 + 1$

$n = 16$

Step 2: Finding the sum of $n$ terms ($S_n$)

We use the formula for the sum of the first $n$ terms of an AP when the first and last terms are known:

$S_n = \frac{n}{2}(a + a_n)$

[Where $S_n$ is the sum of $n$ terms, $n$ is the number of terms, $a$ is the first term, and $a_n$ is the last term.]

Substituting the values $n = 16$, $a = 5$, and $a_n = 50$:

$S_{16} = \frac{16}{2}(5 + 50)$

Simplify the fraction and the expression inside the parentheses:

$S_{16} = 8(55)$

Perform the multiplication:

$S_{16} = 440$

Final Answer: The number of terms $n = 16$ and the sum of the terms $S_n = 440$.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


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