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Q3(vii):
In an AP: (vii) given $a = 8, a_n = 62, S_n = 210$, find $n$ and $d$.

Solution :

Given:

The first term of the Arithmetic Progression (AP), $a = 8$.

The $n^{th}$ term of the AP, $a_n = 62$.

The sum of the first $n$ terms of the AP, $S_n = 210$.

To find:

The number of terms, $n$, and the common difference, $d$.

Step 1: Formulating the equation for $n$ using the sum formula.

The formula for the sum of the first $n$ terms of an AP when the first term ($a$) and the last term ($a_n$) are known is given by:

$S_n = \frac{n}{2}(a + a_n)$

[Substituting the given values into the formula]:

$210 = \frac{n}{2}(8 + 62)$

$210 = \frac{n}{2}(70)$

$210 = n \times 35$

$n = \frac{210}{35}$

$n = 6$

[Since $210 \div 35 = 6$].

Step 2: Formulating the equation for $d$ using the $n^{th}$ term formula.

The formula for the $n^{th}$ term of an AP is given by:

$a_n = a + (n - 1)d$

[Substituting the known values $a_n = 62$, $a = 8$, and $n = 6$]:

$62 = 8 + (6 - 1)d$

$62 = 8 + 5d$

[Subtracting 8 from both sides of the equation]:

$62 - 8 = 5d$

$54 = 5d$

[Dividing both sides by 5]:

$d = \frac{54}{5}$

$d = 10.8$

Summary of Results:

We have determined the number of terms $n$ by utilizing the sum formula for an AP, and subsequently determined the common difference $d$ by substituting $n$ into the general term formula.

Final Answer: $n = 6$ and $d = 10.8$


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


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