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Q14:
Find the sum of the odd numbers between 0 and 50.

Solution :

Given: The range of numbers is between $0$ and $50$. We are interested in the odd numbers within this range.

To Find: The sum of all odd numbers between $0$ and $50$.

Step 1: Identifying the Sequence

The odd numbers between $0$ and $50$ form an Arithmetic Progression (AP) starting from $1$ and ending at $49$.
The sequence is: $1, 3, 5, 7, \dots, 49$.

Here:
First term ($a$) = $1$
Common difference ($d$) = $3 - 1 = 2$
Last term ($a_n$ or $l$) = $49$

Step 2: Determining the Number of Terms ($n$)

We use the formula for the $n^{th}$ term of an Arithmetic Progression:
$a_n = a + (n - 1)d$

Substituting the known values into the formula:
$49 = 1 + (n - 1)2$

Subtract $1$ from both sides:
$49 - 1 = (n - 1)2$
$48 = (n - 1)2$

Divide both sides by $2$:
$\frac{48}{2} = n - 1$
$24 = n - 1$

Add $1$ to both sides:
$n = 24 + 1$
$n = 25$

[Since there are $25$ terms in the sequence]

Step 3: Calculating the Sum of the AP

The formula for the sum of the first $n$ terms of an AP when the last term ($l$) is known is:
$S_n = \frac{n}{2}(a + l)$

Substituting $n = 25$, $a = 1$, and $l = 49$:
$S_{25} = \frac{25}{2}(1 + 49)$

Perform the addition inside the parentheses:
$S_{25} = \frac{25}{2}(50)$

Simplify the expression:
$S_{25} = 25 \times \left(\frac{50}{2}\right)$
$S_{25} = 25 \times 25$

Calculate the product:
$S_{25} = 625$

Final Answer: The sum of the odd numbers between 0 and 50 is 625.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


Other Subjects in CBSE - Class 10

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