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Q10(i):
Show that $a_1, a_2, . . ., a_n, . . .$ form an AP where $a_n$ is defined as below : (i) $a_n = 3 + 4n$ Also find the sum of the first 15 terms in each case.

Solution :

Given: The $n^{th}$ term of a sequence is defined by the expression $a_n = 3 + 4n$.

To Find:
1. Show that the sequence forms an Arithmetic Progression (AP).
2. Calculate the sum of the first 15 terms ($S_{15}$).

Step 1: Generating the terms of the sequence
To determine if the sequence is an AP, we calculate the first few terms by substituting $n = 1, 2, 3, ...$ into the given formula $a_n = 3 + 4n$.

For $n = 1$: $a_1 = 3 + 4(1) = 3 + 4 = 7$
For $n = 2$: $a_2 = 3 + 4(2) = 3 + 8 = 11$
For $n = 3$: $a_3 = 3 + 4(3) = 3 + 12 = 15$
For $n = 4$: $a_4 = 3 + 4(4) = 3 + 16 = 19$

Step 2: Verifying the Arithmetic Progression
A sequence is an AP if the difference between consecutive terms is constant. This constant is called the common difference ($d$).

Calculate the differences:
$a_2 - a_1 = 11 - 7 = 4$
$a_3 - a_2 = 15 - 11 = 4$
$a_4 - a_3 = 19 - 15 = 4$

[Since the difference $a_n - a_{n-1} = 4$ is constant for all $n$, the sequence is an AP with first term $a = 7$ and common difference $d = 4$.]

Step 3: Calculating the sum of the first 15 terms
The formula for the sum of the first $n$ terms of an AP is given by:
$S_n = \frac{n}{2} [2a + (n - 1)d]$

Here, $n = 15$, $a = 7$, and $d = 4$. Substituting these values into the formula:

$S_{15} = \frac{15}{2} [2(7) + (15 - 1)4]$

Step 4: Simplifying the expression
$S_{15} = \frac{15}{2} [14 + (14)4]$
$S_{15} = \frac{15}{2} [14 + 56]$
$S_{15} = \frac{15}{2} [70]$
$S_{15} = 15 \times 35$ [Dividing 70 by 2]

$S_{15} = 525$

Final Answer: The sequence forms an AP with a common difference of 4, and the sum of the first 15 terms is 525.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


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