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Q6:
The first and the last terms of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum?

Solution :

Given:

The first term of the Arithmetic Progression (AP), denoted by $a = 17$.

The last term of the AP, denoted by $l$ or $a_n = 350$.

The common difference of the AP, denoted by $d = 9$.

To Find:

1. The number of terms in the AP, denoted by $n$.

2. The sum of all terms in the AP, denoted by $S_n$.

Step 1: Finding the number of terms ($n$)

We use the formula for the $n^{th}$ term of an Arithmetic Progression:

$a_n = a + (n - 1)d$

Substituting the given values into the formula:

$350 = 17 + (n - 1)9$

Subtract $17$ from both sides of the equation:

$350 - 17 = (n - 1)9$

$333 = (n - 1)9$

Divide both sides by $9$:

$\frac{333}{9} = n - 1$

$37 = n - 1$

Add $1$ to both sides to solve for $n$:

$n = 37 + 1$

$n = 38$

[Since the number of terms must be a positive integer, $n=38$ is valid.]

Step 2: Finding the sum of the terms ($S_n$)

We use the formula for the sum of the first $n$ terms of an AP when the first and last terms are known:

$S_n = \frac{n}{2}(a + l)$

Substituting the values $n = 38$, $a = 17$, and $l = 350$:

$S_{38} = \frac{38}{2}(17 + 350)$

Simplify the fraction and the expression inside the parentheses:

$S_{38} = 19(367)$

Perform the multiplication:

$19 \times 367 = 6973$

Step 3: Verification of calculation

$19 \times 300 = 5700$

$19 \times 60 = 1140$

$19 \times 7 = 133$

$5700 + 1140 + 133 = 6973$

Final Answer: There are 38 terms in the AP, and their sum is 6973.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


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