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Q3(ix):
In an AP: (ix) given $a = 3, n = 8, S = 192$, find $d$.

Solution :

Given:

The first term of the Arithmetic Progression (AP), $a = 3$.

The number of terms in the AP, $n = 8$.

The sum of the first $n$ terms, $S_n = 192$.

To find:

The common difference, $d$.


Step 1: Stating the relevant formula for the sum of an AP.

The sum of the first $n$ terms of an Arithmetic Progression is given by the formula:

$S_n = \frac{n}{2} [2a + (n - 1)d]$

[Where $S_n$ is the sum, $n$ is the number of terms, $a$ is the first term, and $d$ is the common difference.]


Step 2: Substituting the given values into the formula.

Substitute $S_n = 192$, $n = 8$, and $a = 3$ into the equation:

$192 = \frac{8}{2} [2(3) + (8 - 1)d]$


Step 3: Simplifying the equation.

First, simplify the fraction outside the bracket:

$192 = 4 [2(3) + (8 - 1)d]$

Next, perform the arithmetic operations inside the bracket:

$192 = 4 [6 + 7d]$


Step 4: Solving for $d$.

Divide both sides of the equation by 4:

$\frac{192}{4} = 6 + 7d$

$48 = 6 + 7d$

Subtract 6 from both sides to isolate the term containing $d$:

$48 - 6 = 7d$

$42 = 7d$

Divide both sides by 7 to find the value of $d$:

$d = \frac{42}{7}$

$d = 6$


Final Answer: The common difference $d$ is 6.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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