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Q5:
The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

Solution :

Given:

The first term of the Arithmetic Progression (AP), denoted by $a = 5$.

The last term of the AP, denoted by $l$ or $a_n = 45$.

The sum of the $n$ terms of the AP, denoted by $S_n = 400$.

To Find:

1. The number of terms ($n$).

2. The common difference ($d$).

Step 1: Finding the number of terms ($n$)

We use the formula for the sum of an AP when the first and last terms are known:

$S_n = \frac{n}{2}(a + l)$

[Substituting the given values into the formula]

$400 = \frac{n}{2}(5 + 45)$

$400 = \frac{n}{2}(50)$

[Simplifying the expression inside the parentheses and dividing 50 by 2]

$400 = n \times 25$

$n = \frac{400}{25}$

$n = 16$

[Since $n$ represents the number of terms, it must be a positive integer]

Step 2: Finding the common difference ($d$)

We use the formula for the $n^{th}$ term of an AP:

$a_n = a + (n - 1)d$

[Substituting the known values: $a_n = 45$, $a = 5$, and $n = 16$]

$45 = 5 + (16 - 1)d$

$45 = 5 + 15d$

[Subtracting 5 from both sides of the equation]

$45 - 5 = 15d$

$40 = 15d$

[Dividing both sides by 15 to solve for $d$]

$d = \frac{40}{15}$

[Simplifying the fraction by dividing the numerator and denominator by their greatest common divisor, 5]

$d = \frac{8}{3}$

Final Answer: The number of terms is 16 and the common difference is $\frac{8}{3}$.


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