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Q8(i):
A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ?

Solution :

Given:

  • Number of red balls in the bag = $3$
  • Number of black balls in the bag = $5$

To Find:

The probability of drawing a red ball at random from the bag.

Visual Representation:

Bag Contents: Red: 3, Black: 5

Step 1: Determine the total number of possible outcomes.

Let $n(S)$ be the total number of balls in the bag, which represents the total number of elementary events in the sample space.

$n(S) = (\text{Number of red balls}) + (\text{Number of black balls})$

$n(S) = 3 + 5$

$n(S) = 8$

[Since the ball is drawn at random, each ball has an equal probability of being selected.]

Step 2: Determine the number of favorable outcomes.

Let $E$ be the event of drawing a red ball. Let $n(E)$ be the number of favorable outcomes for this event.

$n(E) = \text{Number of red balls}$

$n(E) = 3$

Step 3: Apply the probability formula.

The theoretical probability of an event $E$, denoted by $P(E)$, is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes.

Formula: $P(E) = \frac{n(E)}{n(S)}$

[Substituting the values obtained in Step 1 and Step 2]

$P(\text{Red}) = \frac{3}{8}$

Step 4: Verification of the result.

Since $0 \le P(E) \le 1$ and $0 \le \frac{3}{8} \le 1$, the result is consistent with the axioms of probability.

Final Answer: The probability that the ball drawn is red is $\frac{3}{8}$.


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