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Q15(ii)(b):
Five cards—the ten, jack, queen, king and ace of diamonds, are well-shuffled with their face downwards. One card is then picked up at random. (ii) If the queen is drawn and put aside, what is the probability that the second card picked up is (b) a queen?

Solution :

Given:

A set of five cards consisting of the ten, jack, queen, king, and ace of diamonds. One card (the queen) is drawn and put aside.

To Find:

The probability that the second card picked up is a queen.

Step 1: Defining the Sample Space

Initially, the set of cards is $S = \{10, J, Q, K, A\}$. The total number of cards is $n(S) = 5$.

Step 2: Analyzing the Condition after the First Draw

It is given that the queen is drawn and put aside. We must update the sample space for the second draw.

Let $S'$ be the set of remaining cards after the queen is removed:

$S' = \{10, J, K, A\}$

The total number of remaining cards is $n(S') = 5 - 1 = 4$.

Step 3: Identifying the Favorable Outcomes

We are looking for the probability of drawing a queen as the second card.

Let $E$ be the event of drawing a queen from the remaining cards $S'$.

Looking at the set $S' = \{10, J, K, A\}$, we observe that there are no queens remaining in the deck because the only queen was already removed in the first step.

Therefore, the number of favorable outcomes $n(E) = 0$.

Step 4: Applying the Probability Formula

The probability of an event $P(E)$ is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes:

$P(E) = \frac{n(E)}{n(S')}$

[Substituting the values identified in Step 2 and Step 3]

$P(E) = \frac{0}{4}$

$P(E) = 0$

[Since the event is impossible, the probability is 0]

Final Answer:

Final Answer: 0


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