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Q7:
It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

Solution :

Given:

A group of 3 students is considered. The probability that 2 students do not have the same birthday is given as $P(\text{not same birthday}) = 0.992$.

To find:

The probability that the 2 students have the same birthday, denoted as $P(\text{same birthday})$.

Step 1: Identifying the relationship between complementary events

In probability theory, for any event $E$, the event "not $E$" (denoted as $\overline{E}$) represents the complement of event $E$. The sum of the probability of an event occurring and the probability of the event not occurring is always equal to 1.

Formula: $P(E) + P(\overline{E}) = 1$

[Since the sum of probabilities of all elementary events in a sample space is 1]

Step 2: Defining the variables

Let $E$ be the event that 2 students have the same birthday.

Let $\overline{E}$ be the event that 2 students do not have the same birthday.

Given: $P(\overline{E}) = 0.992$

Step 3: Substituting the values into the formula

Using the identity $P(E) + P(\overline{E}) = 1$:

$P(E) + 0.992 = 1$

Step 4: Solving for $P(E)$

To isolate $P(E)$, subtract $0.992$ from both sides of the equation:

$P(E) = 1 - 0.992$

[Performing the subtraction: $1.000 - 0.992 = 0.008$]

$P(E) = 0.008$

Final Answer: The probability that the 2 students have the same birthday is 0.008.


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