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Q19(ii):

A child has a die whose six faces show the letters as given below:

The die is thrown once. What is the probability of getting (ii) D?

Solution :

Given: A die has six faces marked with the following letters: $A, B, C, D, E, A$.

To Find: The probability of getting the letter $D$ when the die is thrown once.

Visual Representation of the Sample Space:

A B C D E A

Step 1: Define the Sample Space ($S$)
The sample space consists of all possible outcomes when the die is thrown. Based on the given faces:
$S = \{A, B, C, D, E, A\}$
The total number of possible outcomes, denoted by $n(S)$, is the count of elements in the set $S$.
$n(S) = 6$ [Since there are 6 faces on the die]

Step 2: Define the Favorable Event ($E$)
Let $E$ be the event of getting the letter $D$.
Looking at the sample space $S = \{A, B, C, D, E, A\}$, we identify the occurrences of $D$.
The favorable outcomes are $\{D\}$.
The number of favorable outcomes, denoted by $n(E)$, is:
$n(E) = 1$

Step 3: Apply the Probability Formula
The theoretical probability of an event $P(E)$ is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes.
Formula: $P(E) = \frac{n(E)}{n(S)}$ [Definition of Probability for equally likely outcomes]

Step 4: Calculation
Substitute the values obtained in Step 1 and Step 2 into the formula:
$P(D) = \frac{1}{6}$

Final Answer: The probability of getting D is $\frac{1}{6}$.


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