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Q12(iii):

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 14.5 ), and these are equally likely outcomes. What is the probability that it will point at (iii) a number greater than 2?

Solution :

Given: A game of chance involves a spinner with numbers $1, 2, 3, 4, 5, 6, 7, 8$. The outcomes are equally likely.

To Find: The probability that the arrow points at a number greater than $2$.

1 2 3 4 5 6 7 8

Step 1: Identify the Sample Space
The sample space $S$ consists of all possible outcomes of the spinner. Since the spinner has numbers from $1$ to $8$, we have:
$S = \{1, 2, 3, 4, 5, 6, 7, 8\}$
The total number of possible outcomes, denoted by $n(S)$, is $8$.

Step 2: Define the Event
Let $E$ be the event of getting a number greater than $2$.
The numbers in the sample space that are greater than $2$ are $\{3, 4, 5, 6, 7, 8\}$.
Therefore, $E = \{3, 4, 5, 6, 7, 8\}$.

Step 3: Count the Favorable Outcomes
The number of favorable outcomes, denoted by $n(E)$, is the count of elements in set $E$.
$n(E) = 6$

Step 4: Apply the Probability Formula
The probability of an event $P(E)$ is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes:
$P(E) = \frac{n(E)}{n(S)}$
[Using the classical definition of probability]

Step 5: Calculate the Probability
Substitute the values obtained in Step 1 and Step 3 into the formula:
$P(E) = \frac{6}{8}$
To simplify the fraction, divide both the numerator and the denominator by their greatest common divisor, which is $2$:
$P(E) = \frac{6 \div 2}{8 \div 2} = \frac{3}{4}$

Final Answer: The probability that the arrow will point at a number greater than 2 is $\frac{3}{4}$ (or $0.75$).


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