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Q12(i):

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 14.5 ), and these are equally likely outcomes. What is the probability that it will point at (i) 8 ?

Solution :

Given: A game of chance involves a spinner with 8 equal sectors labeled with the numbers $\{1, 2, 3, 4, 5, 6, 7, 8\}$. The arrow is equally likely to stop at any of these numbers.

To Find: The probability that the arrow points at the number $8$.

Visual Representation:

1 2 3 4 5 6 7 8

Step 1: Define the Sample Space
The sample space $S$ is the set of all possible outcomes of the experiment. Since the spinner has 8 numbers, the sample space is:
$S = \{1, 2, 3, 4, 5, 6, 7, 8\}$
The total number of possible outcomes, denoted by $n(S)$, is $8$.

Step 2: Define the Favorable Event
Let $E$ be the event that the arrow points at the number $8$.
The set of favorable outcomes is $E = \{8\}$.
The number of favorable outcomes, denoted by $n(E)$, is $1$.

Step 3: Apply the Probability Formula
The theoretical probability of an event $P(E)$ is defined as the ratio of the number of favorable outcomes to the total number of equally likely outcomes:
$P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$
$P(E) = \frac{n(E)}{n(S)}$

Step 4: Calculation
Substituting the values obtained in Step 1 and Step 2 into the formula:
$P(E) = \frac{1}{8}$

Final Answer: The probability that the arrow will point at 8 is $\frac{1}{8}$.


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