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Q12(iv):

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 14.5 ), and these are equally likely outcomes. What is the probability that it will point at (iv) a number less than 9?

Solution :

Given: A game of chance involves a spinner with 8 equally likely outcomes, represented by the set of numbers $S = \{1, 2, 3, 4, 5, 6, 7, 8\}$.

To Find: The probability that the arrow points at a number less than 9.

1 2 3 4 8 7 6 5

Step 1: Define the Sample Space
The sample space $S$ consists of all possible outcomes of the spinner. Since the numbers are 1 through 8:
$S = \{1, 2, 3, 4, 5, 6, 7, 8\}$
The total number of possible outcomes, denoted by $n(S)$, is 8.

Step 2: Define the Event
Let $E$ be the event that the arrow points at a number less than 9.
By examining the set $S$, we identify the numbers that satisfy the condition $x < 9$:
$E = \{1, 2, 3, 4, 5, 6, 7, 8\}$
The number of favorable outcomes, denoted by $n(E)$, is 8.

Step 3: Apply the Probability Formula
The probability of an event $P(E)$ is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes:
$P(E) = \frac{n(E)}{n(S)}$
[Using the classical definition of probability for equally likely outcomes]

Step 4: Calculation
Substitute the values obtained in Step 1 and Step 2 into the formula:
$P(E) = \frac{8}{8}$
$P(E) = 1$

Justification: Since every number on the spinner is less than 9, the event $E$ is a sure event (or certain event). The probability of a sure event is always 1.

Final Answer: The probability that the arrow will point at a number less than 9 is 1.


More Questions from Class 10 Mathematics Probability EXERCISE 14.1


CBSE Solutions for Class 10 Mathematics Probability


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