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Q4(xiv):
Which of the following are APs ? If they form an AP, find the common difference $d$ and write three more terms. (xiv) $1^2, 3^2, 5^2, 7^2, . . .$

Solution :

Given: A sequence of numbers $1^2, 3^2, 5^2, 7^2, \dots$

To Find: Determine if the sequence forms an Arithmetic Progression (AP). If it does, find the common difference $d$ and the next three terms.

Step 1: Evaluating the terms of the sequence

Let the sequence be denoted by $a_1, a_2, a_3, a_4, \dots$

Calculating the values of the given terms:

$a_1 = 1^2 = 1$

$a_2 = 3^2 = 9$

$a_3 = 5^2 = 25$

$a_4 = 7^2 = 49$

The sequence is $1, 9, 25, 49, \dots$

Step 2: Checking for a common difference

A sequence is an AP if the difference between consecutive terms is constant, i.e., $a_{n+1} - a_n = d$ for all $n$.

Calculate the difference between the first and second terms ($d_1$):

$d_1 = a_2 - a_1 = 9 - 1 = 8$

Calculate the difference between the second and third terms ($d_2$):

$d_2 = a_3 - a_2 = 25 - 9 = 16$

Calculate the difference between the third and fourth terms ($d_3$):

$d_3 = a_4 - a_3 = 49 - 25 = 24$

Step 3: Conclusion on the nature of the sequence

Since $d_1 \neq d_2 \neq d_3$ (specifically, $8 \neq 16 \neq 24$), the difference between consecutive terms is not constant.

[Definition of an Arithmetic Progression: A sequence is an AP if and only if the difference between any two consecutive terms is constant.]

Final Answer: The given sequence $1^2, 3^2, 5^2, 7^2, \dots$ does not form an Arithmetic Progression because the common difference is not constant.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


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