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Q3(iv):
For the following APs, write the first term and the common difference: (iv) 0.6, 1.7, 2.8, 3.9, . . .

Solution :

Given: An arithmetic progression (AP) series: $0.6, 1.7, 2.8, 3.9, \dots$

To Find: The first term ($a$) and the common difference ($d$) of the given arithmetic progression.

Step 1: Identifying the First Term

In an arithmetic progression, the first term is denoted by the variable $a$ (or $a_1$). By observing the given sequence:

The sequence is: $a_1 = 0.6, a_2 = 1.7, a_3 = 2.8, a_4 = 3.9, \dots$

Therefore, the first term $a = 0.6$.

Step 2: Defining the Common Difference

The common difference ($d$) of an arithmetic progression is the constant value obtained by subtracting any term from the term that immediately follows it. The formula is defined as:

$d = a_{n} - a_{n-1}$

For this sequence, we can calculate $d$ using the first two terms:

$d = a_2 - a_1$

Step 3: Calculating the Common Difference

Substitute the values of $a_2$ and $a_1$ into the formula:

$d = 1.7 - 0.6$

Performing the subtraction:

$d = 1.1$

Step 4: Verification (Optional but Recommended)

To ensure the sequence is indeed an AP, we verify the difference between subsequent terms:

$a_3 - a_2 = 2.8 - 1.7 = 1.1$

$a_4 - a_3 = 3.9 - 2.8 = 1.1$

[Since the difference remains constant at $1.1$, the common difference is confirmed.]

Final Answer: The first term $a = 0.6$ and the common difference $d = 1.1$.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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