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Q4(i):
Which of the following are APs ? If they form an AP, find the common difference $d$ and write three more terms. (i) 2, 4, 8, 16, . . .

Solution :

Given: A sequence of numbers: $2, 4, 8, 16, \dots$

To Find:
1. Determine if the given sequence forms an Arithmetic Progression (AP).
2. If it forms an AP, find the common difference $d$ and the next three terms.

Step 1: Definition and Condition for an Arithmetic Progression
A sequence $a_1, a_2, a_3, a_4, \dots$ is said to be an Arithmetic Progression if the difference between consecutive terms remains constant. This constant difference is called the common difference ($d$).
Mathematically, the condition is:
$a_2 - a_1 = a_3 - a_2 = a_4 - a_3 = d$

Step 2: Calculating the differences between consecutive terms
Let the given terms be:
$a_1 = 2$
$a_2 = 4$
$a_3 = 8$
$a_4 = 16$

Now, calculate the differences:
Difference 1 ($d_1$): $a_2 - a_1 = 4 - 2 = 2$
Difference 2 ($d_2$): $a_3 - a_2 = 8 - 4 = 4$
Difference 3 ($d_3$): $a_4 - a_3 = 16 - 8 = 8$

Step 3: Analyzing the results
Comparing the differences obtained:
$d_1 = 2$
$d_2 = 4$
$d_3 = 8$

Since $d_1 \neq d_2 \neq d_3$, the difference between consecutive terms is not constant.
[By the definition of an Arithmetic Progression, a sequence must have a constant common difference to be classified as an AP.]

Step 4: Conclusion
Because the common difference is not constant, the sequence $2, 4, 8, 16, \dots$ does not form an Arithmetic Progression.

Final Answer: The given sequence $2, 4, 8, 16, \dots$ does not form an AP because the difference between consecutive terms is not constant.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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