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Q2(v):
Write first four terms of the AP, when the first term $a$ and the common difference $d$ are given as follows: (v) $a = – 1.25, d = – 0.25$

Solution :

Given: The first term of the Arithmetic Progression (AP) is $a = -1.25$ and the common difference is $d = -0.25$.

To Find: The first four terms of the Arithmetic Progression.

Step 1: Understanding the definition of an Arithmetic Progression
An Arithmetic Progression is a sequence of numbers such that the difference between consecutive terms is constant. This constant difference is denoted by $d$. If the first term is $a$, the terms of the AP are given by the general form: $a, a+d, a+2d, a+3d, \dots$

Step 2: Calculating the first four terms
Let the terms be denoted as $a_1, a_2, a_3,$ and $a_4$.

Calculation for the first term ($a_1$):
$a_1 = a$
$a_1 = -1.25$

Calculation for the second term ($a_2$):
$a_2 = a + d$
$a_2 = -1.25 + (-0.25)$
$a_2 = -1.25 - 0.25$
$a_2 = -1.50$

Calculation for the third term ($a_3$):
$a_3 = a_2 + d$
$a_3 = -1.50 + (-0.25)$
$a_3 = -1.50 - 0.25$
$a_3 = -1.75$

Calculation for the fourth term ($a_4$):
$a_4 = a_3 + d$
$a_4 = -1.75 + (-0.25)$
$a_4 = -1.75 - 0.25$
$a_4 = -2.00$

Step 3: Summary of the sequence
The first four terms of the AP are $-1.25, -1.50, -1.75,$ and $-2.00$.

Final Answer: The first four terms of the AP are $-1.25, -1.50, -1.75, -2.00$.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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