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Q4(vi):
Which of the following are APs ? If they form an AP, find the common difference $d$ and write three more terms. (vi) 0.2, 0.22, 0.222, 0.2222, . . .

Solution :

Given: A sequence of numbers: $0.2, 0.22, 0.222, 0.2222, \dots$

To Find: Determine if the given sequence forms an Arithmetic Progression (AP). If it does, find the common difference $d$ and write the next three terms.

Step 1: Definition of an Arithmetic Progression
An Arithmetic Progression is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant difference is called the common difference ($d$).
For a sequence $a_1, a_2, a_3, a_4, \dots$, the sequence is an AP if and only if:
$a_2 - a_1 = a_3 - a_2 = a_4 - a_3 = d$

Step 2: Calculating the differences between consecutive terms
Let the terms be:
$a_1 = 0.2$
$a_2 = 0.22$
$a_3 = 0.222$
$a_4 = 0.2222$

Calculate the difference between the first and second term ($d_1$):
$d_1 = a_2 - a_1 = 0.22 - 0.2 = 0.02$

Calculate the difference between the second and third term ($d_2$):
$d_2 = a_3 - a_2 = 0.222 - 0.22 = 0.002$

Calculate the difference between the third and fourth term ($d_3$):
$d_3 = a_4 - a_3 = 0.2222 - 0.222 = 0.0002$

Step 3: Comparing the differences
We observe that:
$d_1 = 0.02$
$d_2 = 0.002$
$d_3 = 0.0002$
Since $d_1 \neq d_2 \neq d_3$, the difference between consecutive terms is not constant.

Step 4: Conclusion
Because the common difference is not constant, the given sequence $0.2, 0.22, 0.222, 0.2222, \dots$ does not satisfy the condition for an Arithmetic Progression.

Final Answer: The given sequence does not form an AP because the difference between consecutive terms is not constant.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


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