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Q4(iv):
Which of the following are APs ? If they form an AP, find the common difference $d$ and write three more terms. (iv) – 10, – 6, – 2, 2, . . .

Solution :

Given: A sequence of numbers: $-10, -6, -2, 2, \dots$

To Find:
1. Determine if the given sequence forms an Arithmetic Progression (AP).
2. If it forms an AP, find the common difference ($d$).
3. Write the next three terms of the sequence.

Step 1: Defining the terms of the sequence
Let the given sequence be represented by $a_1, a_2, a_3, a_4, \dots$ where:
$a_1 = -10$
$a_2 = -6$
$a_3 = -2$
$a_4 = 2$

Step 2: Checking for a common difference
A sequence is an Arithmetic Progression if the difference between consecutive terms is constant. This constant is called the common difference ($d$).
We calculate the differences between consecutive terms:

$d_1 = a_2 - a_1 = -6 - (-10) = -6 + 10 = 4$
$d_2 = a_3 - a_2 = -2 - (-6) = -2 + 6 = 4$
$d_3 = a_4 - a_3 = 2 - (-2) = 2 + 2 = 4$

Step 3: Verification of AP
Since $d_1 = d_2 = d_3 = 4$, the difference between consecutive terms is constant.
[Definition: An Arithmetic Progression is a sequence of numbers such that the difference between the consecutive terms is constant.]
Therefore, the given sequence is an AP with a common difference $d = 4$.

Step 4: Finding the next three terms
To find the next terms, we add the common difference $d = 4$ to the preceding term.
Let the next three terms be $a_5, a_6,$ and $a_7$.

Calculation for $a_5$:
$a_5 = a_4 + d = 2 + 4 = 6$

Calculation for $a_6$:
$a_6 = a_5 + d = 6 + 4 = 10$

Calculation for $a_7$:
$a_7 = a_6 + d = 10 + 4 = 14$

Final Answer:
The sequence forms an AP.
The common difference $d = 4$.
The next three terms are 6, 10, 14.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


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