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Q3(i):
For the following APs, write the first term and the common difference: (i) 3, 1, – 1, – 3, . . .

Solution :

Given: An Arithmetic Progression (AP) sequence: $3, 1, -1, -3, \dots$

To Find: The first term ($a$) and the common difference ($d$) of the given AP.

Step 1: Defining the variables of an Arithmetic Progression

An Arithmetic Progression is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant difference is known as the common difference ($d$), and the first number in the sequence is denoted as the first term ($a$).

The sequence is represented as: $a_1, a_2, a_3, a_4, \dots, a_n$

Step 2: Identifying the first term ($a$)

By definition, the first term ($a$) is the first element of the sequence.

Given sequence: $3, 1, -1, -3, \dots$

Therefore, $a = a_1 = 3$.

Step 3: Calculating the common difference ($d$)

The common difference ($d$) is calculated by subtracting any term from the term that immediately follows it. The formula is given by:

$d = a_{n} - a_{n-1}$

Let us calculate $d$ using the first two terms ($a_1$ and $a_2$):

$d = a_2 - a_1$

$d = 1 - 3$

$d = -2$

Step 4: Verification of the common difference

To ensure the sequence is indeed an AP, we verify the difference across other consecutive terms:

For $a_3$ and $a_2$: $d = a_3 - a_2 = -1 - 1 = -2$

For $a_4$ and $a_3$: $d = a_4 - a_3 = -3 - (-1) = -3 + 1 = -2$

[Since the difference is constant across all tested terms, the common difference $d = -2$ is verified.]

Final Answer: The first term $a = 3$ and the common difference $d = -2$.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


Other Subjects in CBSE - Class 10

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