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Q4(ii):
Which of the following are APs ? If they form an AP, find the common difference $d$ and write three more terms. (ii) $2, \frac{5}{2}, 3, \frac{7}{2}, . . .$

Solution :

Given: A sequence of numbers: $2, \frac{5}{2}, 3, \frac{7}{2}, \dots$

To find:
1. Determine if the given sequence forms an Arithmetic Progression (AP).
2. If it forms an AP, find the common difference ($d$).
3. Write the next three terms of the sequence.

Step 1: Identifying the terms of the sequence

Let the sequence be denoted by $a_1, a_2, a_3, a_4, \dots$
$a_1 = 2$
$a_2 = \frac{5}{2}$
$a_3 = 3$
$a_4 = \frac{7}{2}$

Step 2: Checking for a common difference

A sequence is an AP if the difference between consecutive terms is constant. This constant is called the common difference ($d$).
Calculate the difference between consecutive terms:

Difference $d_1 = a_2 - a_1 = \frac{5}{2} - 2 = \frac{5}{2} - \frac{4}{2} = \frac{1}{2}$

Difference $d_2 = a_3 - a_2 = 3 - \frac{5}{2} = \frac{6}{2} - \frac{5}{2} = \frac{1}{2}$

Difference $d_3 = a_4 - a_3 = \frac{7}{2} - 3 = \frac{7}{2} - \frac{6}{2} = \frac{1}{2}$

Step 3: Conclusion on AP status

[Since $d_1 = d_2 = d_3 = \frac{1}{2}$, the difference between consecutive terms is constant.]
Therefore, the given sequence is an Arithmetic Progression with a common difference $d = \frac{1}{2}$.

Step 4: Finding the next three terms

To find the next terms, we add the common difference $d = \frac{1}{2}$ to the last known term ($a_4 = \frac{7}{2}$).

Fifth term ($a_5$) = $a_4 + d = \frac{7}{2} + \frac{1}{2} = \frac{8}{2} = 4$

Sixth term ($a_6$) = $a_5 + d = 4 + \frac{1}{2} = \frac{8}{2} + \frac{1}{2} = \frac{9}{2}$

Seventh term ($a_7$) = $a_6 + d = \frac{9}{2} + \frac{1}{2} = \frac{10}{2} = 5$

Final Answer: The sequence forms an AP with common difference $d = \frac{1}{2}$. The next three terms are $4, \frac{9}{2}, 5$.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


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