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Q7:
Draw the graphs of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.

Solution :

Given: Two linear equations in two variables:
1) $x - y + 1 = 0$
2) $3x + 2y - 12 = 0$

To Find: The coordinates of the vertices of the triangle formed by these two lines and the x-axis, and to represent the region graphically.

x y O

Step 1: Finding coordinates for the first equation $x - y + 1 = 0$
Rearranging the equation: $y = x + 1$.
If $x = -1$, then $y = 0$. Point: $(-1, 0)$
If $x = 0$, then $y = 1$. Point: $(0, 1)$
If $x = 1$, then $y = 2$. Point: $(1, 2)$

Step 2: Finding coordinates for the second equation $3x + 2y - 12 = 0$
Rearranging the equation: $2y = 12 - 3x \implies y = \frac{12 - 3x}{2}$.
If $x = 0$, then $y = 6$. Point: $(0, 6)$
If $x = 2$, then $y = 3$. Point: $(2, 3)$
If $x = 4$, then $y = 0$. Point: $(4, 0)$

Step 3: Determining the intersection point of the two lines
We solve the system of equations:
(i) $x - y = -1 \implies y = x + 1$
(ii) $3x + 2y = 12$
Substitute (i) into (ii):
$3x + 2(x + 1) = 12$
$3x + 2x + 2 = 12$
$5x = 10 \implies x = 2$
Substitute $x = 2$ into $y = x + 1$:
$y = 2 + 1 = 3$
The intersection point is $(2, 3)$.

Step 4: Identifying the vertices of the triangle
The triangle is formed by the two lines and the x-axis ($y=0$).
- The first line $x - y + 1 = 0$ intersects the x-axis at $y=0 \implies x = -1$. Vertex: $(-1, 0)$.
- The second line $3x + 2y - 12 = 0$ intersects the x-axis at $y=0 \implies 3x = 12 \implies x = 4$. Vertex: $(4, 0)$.
- The two lines intersect at $(2, 3)$. Vertex: $(2, 3)$.

Final Answer: The vertices of the triangle formed are $(-1, 0)$, $(4, 0)$, and $(2, 3)$.


More Questions from Class 10 Mathematics Pair of linear equations in two variable EXERCISE 3.1


CBSE Solutions for Class 10 Mathematics Pair of linear equations in two variable


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