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Q6(i):
Given the linear equation 2x + 3y – 8 = 0, write another linear equation in two variables such that the geometrical representation of the pair so formed is: (i) intersecting lines

Solution :

Given: A linear equation in two variables, $2x + 3y - 8 = 0$.

To Find: Another linear equation in two variables, $a_2x + b_2y + c_2 = 0$, such that the pair of linear equations represents intersecting lines.

Theoretical Context:

For a pair of linear equations in two variables given by:

$a_1x + b_1y + c_1 = 0$

$a_2x + b_2y + c_2 = 0$

The lines are intersecting if and only if the ratio of the coefficients of $x$ and $y$ are not equal, i.e.,

$\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$

Intersection Point Line 1 Line 2

Step 1: Identify the coefficients of the given equation.

The given equation is $2x + 3y - 8 = 0$.

Comparing this with $a_1x + b_1y + c_1 = 0$, we have:

$a_1 = 2$

$b_1 = 3$

$c_1 = -8$

Step 2: Formulate the condition for intersecting lines.

We need to choose $a_2$ and $b_2$ such that:

$\frac{2}{a_2} \neq \frac{3}{b_2}$

This implies $2b_2 \neq 3a_2$.

Step 3: Select arbitrary values for $a_2$ and $b_2$ satisfying the condition.

Let us choose $a_2 = 3$ and $b_2 = 2$.

Checking the condition: $\frac{a_1}{a_2} = \frac{2}{3}$ and $\frac{b_1}{b_2} = \frac{3}{2}$.

Since $\frac{2}{3} \neq \frac{3}{2}$, the condition for intersecting lines is satisfied.

Step 4: Write the final equation.

We can choose any constant $c_2$. Let $c_2 = -7$.

Substituting these values into the general form $a_2x + b_2y + c_2 = 0$, we get:

$3x + 2y - 7 = 0$

Verification:

For the pair $2x + 3y - 8 = 0$ and $3x + 2y - 7 = 0$:

$\frac{a_1}{a_2} = \frac{2}{3}$

$\frac{b_1}{b_2} = \frac{3}{2}$

Since $\frac{2}{3} \neq \frac{3}{2}$, the lines intersect at a unique point.

Final Answer: One such equation is $3x + 2y - 7 = 0$ (Note: Many other solutions are possible, such as $x + y - 1 = 0$).


More Questions from Class 10 Mathematics Pair of linear equations in two variable EXERCISE 3.1


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