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Q5:
Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

Solution :

Given:

1. The garden is rectangular in shape.

2. The length of the garden is $4\text{ m}$ more than its width.

3. The half-perimeter of the garden is $36\text{ m}$.

To Find:

The dimensions (length and width) of the rectangular garden.

Length (l) Width (w)

Step 1: Defining Variables

Let the width of the rectangular garden be $w$ meters.

Let the length of the rectangular garden be $l$ meters.

Step 2: Formulating the Equations

Based on the given conditions:

Condition 1: The length is $4\text{ m}$ more than the width.

$l = w + 4$ --- (Equation 1)

Condition 2: The half-perimeter of the rectangle is $36\text{ m}$.

The formula for the perimeter of a rectangle is $P = 2(l + w)$.

Therefore, the half-perimeter is $\frac{P}{2} = l + w$.

$l + w = 36$ --- (Equation 2)

Step 3: Solving the System of Equations

We have a system of two linear equations in two variables:

1) $l - w = 4$

2) $l + w = 36$

Substitute Equation 1 into Equation 2 [Using the Substitution Method]:

$(w + 4) + w = 36$

$2w + 4 = 36$

Subtract $4$ from both sides [Addition Property of Equality]:

$2w = 36 - 4$

$2w = 32$

Divide both sides by $2$ [Division Property of Equality]:

$w = \frac{32}{2}$

$w = 16$

Step 4: Finding the Length

Substitute the value of $w = 16$ back into Equation 1:

$l = 16 + 4$

$l = 20$

Step 5: Verification

Check the conditions:

Length ($20$) is $4$ more than width ($16$): $20 - 16 = 4$ (Correct).

Half-perimeter: $l + w = 20 + 16 = 36$ (Correct).

Final Answer: The dimensions of the garden are length = 20 m and width = 16 m.


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