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Q6(iii):
Given the linear equation 2x + 3y – 8 = 0, write another linear equation in two variables such that the geometrical representation of the pair so formed is: (iii) coincident lines

Solution :

Given: A linear equation in two variables, $2x + 3y - 8 = 0$.

To Find: Another linear equation in two variables, $a_2x + b_2y + c_2 = 0$, such that the pair of linear equations represents coincident lines.

Theoretical Background:

For a pair of linear equations in two variables given by:

$a_1x + b_1y + c_1 = 0$

$a_2x + b_2y + c_2 = 0$

The lines are coincident if and only if the ratios of their coefficients are equal, satisfying the condition:

$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$

Step 1: Identify the coefficients of the given equation.

The given equation is $2x + 3y - 8 = 0$.

Comparing this with the standard form $a_1x + b_1y + c_1 = 0$, we have:

$a_1 = 2$

$b_1 = 3$

$c_1 = -8$

Step 2: Apply the condition for coincident lines.

To obtain a coincident line, we can multiply the entire equation by a non-zero constant $k$. Let us choose $k = 2$ for simplicity.

The new coefficients will be:

$a_2 = k \cdot a_1 = 2 \cdot 2 = 4$

$b_2 = k \cdot b_1 = 2 \cdot 3 = 6$

$c_2 = k \cdot c_1 = 2 \cdot (-8) = -16$

Step 3: Formulate the new equation.

Substituting the values of $a_2, b_2,$ and $c_2$ into the standard form $a_2x + b_2y + c_2 = 0$:

$4x + 6y - 16 = 0$

Step 4: Verification of the condition.

Check the ratios:

$\frac{a_1}{a_2} = \frac{2}{4} = \frac{1}{2}$

$\frac{b_1}{b_2} = \frac{3}{6} = \frac{1}{2}$

$\frac{c_1}{c_2} = \frac{-8}{-16} = \frac{1}{2}$

[Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$, the lines are coincident.]

Final Answer: One such linear equation is 4x + 6y - 16 = 0.


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