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Q3(ii):
On comparing the ratios $\frac{a_1}{a_2}$, $\frac{b_1}{b_2}$, and $\frac{c_1}{c_2}$, find out whether the following pair of linear equations are consistent, or inconsistent. (ii) 2x – 3y = 8 ; 4x – 6y = 9

Solution :

Given: A pair of linear equations in two variables:

Equation 1: $2x - 3y = 8$

Equation 2: $4x - 6y = 9$

To Find: Determine whether the given pair of linear equations is consistent or inconsistent by comparing the ratios $\frac{a_1}{a_2}$, $\frac{b_1}{b_2}$, and $\frac{c_1}{c_2}$.

Step 1: Standardizing the Equations

The standard form of a linear equation in two variables is $ax + by + c = 0$. We rewrite the given equations in this form:

Equation 1: $2x - 3y - 8 = 0$

Equation 2: $4x - 6y - 9 = 0$

Step 2: Identifying Coefficients

Comparing these with the general forms $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$, we identify:

For Equation 1: $a_1 = 2$, $b_1 = -3$, $c_1 = -8$

For Equation 2: $a_2 = 4$, $b_2 = -6$, $c_2 = -9$

Step 3: Calculating the Ratios

We calculate the ratios of the coefficients:

Ratio of $x$-coefficients: $\frac{a_1}{a_2} = \frac{2}{4} = \frac{1}{2}$

Ratio of $y$-coefficients: $\frac{b_1}{b_2} = \frac{-3}{-6} = \frac{1}{2}$

Ratio of constants: $\frac{c_1}{c_2} = \frac{-8}{-9} = \frac{8}{9}$

Step 4: Comparing the Ratios and Applying the Consistency Condition

We observe the following relationship between the ratios:

$\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$

Since $\frac{1}{2} = \frac{1}{2} \neq \frac{8}{9}$, the condition for parallel lines (no solution) is satisfied.

[Theorem: If $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$, the lines are parallel and the system of equations has no solution, making it inconsistent.]

Final Answer: Since the ratios satisfy the condition $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$, the given pair of linear equations is inconsistent.


More Questions from Class 10 Mathematics Pair of linear equations in two variable EXERCISE 3.1


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