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Q8(i):

A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see Fig. 11.8). Find (i) the area of that part of the field in which the horse can graze. (Use $\pi = 3.14$)

Solution :

Given:

  • A square-shaped grass field with side length $s = 15\text{ m}$.
  • A horse is tied to one corner of the square field.
  • The length of the rope, which acts as the radius $r$ of the grazing area, is $r = 5\text{ m}$.

To Find:

The area of the part of the field in which the horse can graze.

15 m 15 m 5 m Peg

Step 1: Understanding the Geometry of the Grazing Area

Since the horse is tied to a corner of a square field, the angle at the corner of the square is $90^\circ$. The horse can move within a circular sector defined by the length of the rope. Therefore, the grazing area is a sector of a circle with radius $r = 5\text{ m}$ and central angle $\theta = 90^\circ$.

Step 2: Formula for the Area of a Sector

The formula for the area of a sector of a circle is given by:

$\text{Area of Sector} = \frac{\theta}{360^\circ} \times \pi r^2$

[Where $\theta$ is the central angle in degrees and $r$ is the radius of the circle.]

Step 3: Substituting the Given Values

Given values: $\theta = 90^\circ$, $r = 5\text{ m}$, and $\pi = 3.14$.

$\text{Area} = \frac{90^\circ}{360^\circ} \times 3.14 \times (5)^2$

Step 4: Performing the Calculation

First, simplify the fraction:

$\frac{90}{360} = \frac{1}{4}$

Next, calculate the square of the radius:

$(5)^2 = 25$

Now, substitute these back into the equation:

$\text{Area} = \frac{1}{4} \times 3.14 \times 25$

$\text{Area} = \frac{78.5}{4}$

$\text{Area} = 19.625\text{ m}^2$

Final Answer: The area of the part of the field in which the horse can graze is 19.625 m².


More Questions from Class 10 Mathematics Areas Related to Circles EXERCISE 11.1


CBSE Solutions for Class 10 Mathematics Areas Related to Circles


Chapters in CBSE - Class 10 Mathematics


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