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Q6:
A chord of a circle of radius 15 cm subtends an angle of 60° at the centre. Find the areas of the corresponding minor and major segments of the circle. (Use $\pi = 3.14$ and $\sqrt{3} = 1.73$)

Solution :

Given:

Radius of the circle ($r$) = $15\text{ cm}$

Angle subtended by the chord at the centre ($\theta$) = $60^\circ$

Constants: $\pi = 3.14$, $\sqrt{3} = 1.73$

To Find:

1. Area of the minor segment.

2. Area of the major segment.


O r=15 60°

Step 1: Calculate the Area of the Sector

The formula for the area of a sector is: $A_{sector} = \frac{\theta}{360^\circ} \times \pi r^2$

$A_{sector} = \frac{60}{360} \times 3.14 \times (15)^2$

$A_{sector} = \frac{1}{6} \times 3.14 \times 225$

$A_{sector} = \frac{706.5}{6} = 117.75\text{ cm}^2$


Step 2: Calculate the Area of the Triangle (OAB)

Since the angle at the centre is $60^\circ$ and the two sides are radii ($OA = OB = 15\text{ cm}$), the triangle is equilateral. The area of an equilateral triangle is given by: $A_{triangle} = \frac{\sqrt{3}}{4} \times r^2$

$A_{triangle} = \frac{1.73}{4} \times (15)^2$

$A_{triangle} = \frac{1.73}{4} \times 225$

$A_{triangle} = \frac{389.25}{4} = 97.3125\text{ cm}^2$


Step 3: Calculate the Area of the Minor Segment

The area of the minor segment is the difference between the area of the sector and the area of the triangle.

$A_{minor\_segment} = A_{sector} - A_{triangle}$

$A_{minor\_segment} = 117.75 - 97.3125 = 20.4375\text{ cm}^2$


Step 4: Calculate the Area of the Major Segment

The area of the major segment is the total area of the circle minus the area of the minor segment.

$A_{circle} = \pi r^2 = 3.14 \times (15)^2 = 3.14 \times 225 = 706.5\text{ cm}^2$

$A_{major\_segment} = A_{circle} - A_{minor\_segment}$

$A_{major\_segment} = 706.5 - 20.4375 = 686.0625\text{ cm}^2$


Final Answer: The area of the minor segment is 20.4375 cm² and the area of the major segment is 686.0625 cm².


More Questions from Class 10 Mathematics Areas Related to Circles EXERCISE 11.1


CBSE Solutions for Class 10 Mathematics Areas Related to Circles


Chapters in CBSE - Class 10 Mathematics


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