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Q4(i):
Expand each of the following, using suitable identities: (i) $(x + 2y + 4z)^2$

Solution :

Initial Setup & Algebraic Identity

We are tasked with expanding the algebraic expression $(x + 2y + 4z)^2$. To execute this expansion systematically, we utilize the standard algebraic identity for the square of a trinomial.

[Per the distributive property of multiplication over addition, the square of a trinomial is given by the identity:]

$(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$

Step 1: Variable Mapping

By comparing our given expression $(x + 2y + 4z)^2$ with the standard identity $(a + b + c)^2$, we establish a direct one-to-one mapping of the terms:

  • $a = x$
  • $b = 2y$
  • $c = 4z$

Geometric Visualization of the Identity

The algebraic expansion of $(a + b + c)^2$ can be geometrically interpreted as the area of a square with side length $(a + b + c)$, partitioned into nine distinct rectangular and square regions. The sum of the areas of these nine regions perfectly mirrors the terms in our algebraic identity.

a² ab ac ab b² bc ac bc c² a b c a b c

Step 2: Substitution into the Identity

Substituting the mapped variables into the right-hand side of the identity, we obtain the unsimplified expanded form:

$(x + 2y + 4z)^2 = (x)^2 + (2y)^2 + (4z)^2 + 2(x)(2y) + 2(2y)(4z) + 2(4z)(x)$

Step 3: Term-by-Term Simplification

We now apply the laws of exponents [specifically $(xy)^n = x^n y^n$] and basic arithmetic multiplication to simplify each term independently.

Term Category Unsimplified Term Algebraic Operation Simplified Result
Square of First Term $(x)^2$ $x \cdot x$ $x^2$
Square of Second Term $(2y)^2$ $2^2 \cdot y^2$ $4y^2$
Square of Third Term $(4z)^2$ $4^2 \cdot z^2$ $16z^2$
First Cross-Product $2(x)(2y)$ $(2 \cdot 2) \cdot (x \cdot y)$ $4xy$
Second Cross-Product $2(2y)(4z)$ $(2 \cdot 2 \cdot 4) \cdot (y \cdot z)$ $16yz$
Third Cross-Product $2(4z)(x)$ $(2 \cdot 4) \cdot (z \cdot x)$ $8zx$

Step 4: Final Assembly

Combining all the simplified terms from Step 3 yields the fully expanded polynomial. By convention, we write the squared terms first, followed by the cross-product terms in cyclical order ($xy$, $yz$, $zx$).

$(x + 2y + 4z)^2 = x^2 + 4y^2 + 16z^2 + 4xy + 16yz + 8zx$

Final Solution: The expanded form of $(x + 2y + 4z)^2$ is $x^2 + 4y^2 + 16z^2 + 4xy + 16yz + 8zx$.


More Questions from Class 9 Mathematics Polynomials EXERCISE 2.4


CBSE Solutions for Class 9 Mathematics Polynomials


Chapters in CBSE - Class 9 Mathematics


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