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Q2(ii):
Represent the following situations in the form of quadratic equations : (ii) The product of two consecutive positive integers is $306$. We need to find the integers.

Solution :

Given: The product of two consecutive positive integers is $306$.

To find: Represent the given situation in the form of a quadratic equation.

Step 1: Defining the variables

Let the first positive integer be $x$.

Since the integers are consecutive, the next integer must be $x + 1$.

[Assumption: $x$ is a positive integer, therefore $x > 0$].

Step 2: Formulating the equation based on the given condition

According to the problem, the product of these two consecutive integers is $306$.

Mathematically, this is expressed as:

$x(x + 1) = 306$

Step 3: Expanding the expression

Distribute $x$ into the parentheses:

$x^2 + x = 306$

Step 4: Rearranging into standard quadratic form

A quadratic equation is represented in the standard form $ax^2 + bx + c = 0$.

Subtract $306$ from both sides of the equation to set the right side to zero:

$x^2 + x - 306 = 0$

Step 5: Verification of the form

Comparing $x^2 + x - 306 = 0$ with the standard form $ax^2 + bx + c = 0$:

Here, $a = 1$, $b = 1$, and $c = -306$.

Since the highest power of the variable $x$ is $2$, this is a quadratic equation.

Final Answer: The quadratic equation representing the given situation is $x^2 + x - 306 = 0$, where $x$ is the smaller integer.


More Questions from Class 10 Mathematics Quadratic Equations EXERCISE 4.1


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