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Q14:
How many multiples of 4 lie between 10 and 250?

Solution :

Given: The range of numbers is between 10 and 250. We are looking for multiples of 4 within this range.

To find: The total number of multiples of 4 that lie between 10 and 250.

Step 1: Identifying the first and last terms of the Arithmetic Progression (AP)

To find the first multiple of 4 after 10: $10 \div 4 = 2$ with a remainder of $2$. The next multiple is $4 \times 3 = 12$. Thus, the first term ($a$) is $12$.

To find the last multiple of 4 before 250: $250 \div 4 = 62.5$. The largest integer multiple is $4 \times 62 = 248$. Thus, the last term ($a_n$) is $248$.

Step 2: Defining the Arithmetic Progression

The sequence of multiples of 4 between 10 and 250 is: $12, 16, 20, \dots, 248$.

Here, the first term $a = 12$.
The common difference $d = 16 - 12 = 4$.
The $n^{th}$ term $a_n = 248$.

Step 3: Applying the formula for the $n^{th}$ term of an AP

The formula for the $n^{th}$ term of an Arithmetic Progression is given by: $a_n = a + (n - 1)d$

Substituting the known values into the formula: $248 = 12 + (n - 1)4$

Step 4: Solving for $n$

Subtract 12 from both sides: $248 - 12 = (n - 1)4$ $236 = (n - 1)4$

Divide both sides by 4: $\frac{236}{4} = n - 1$ $59 = n - 1$

Add 1 to both sides: $n = 59 + 1$ $n = 60$

Justification: Since the sequence is finite and follows a constant common difference, the number of terms $n$ represents the count of multiples of 4 within the specified interval.

Final Answer: There are 60 multiples of 4 that lie between 10 and 250.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.2


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


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