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Q1(ii):
Fill in the blanks in the following table, given that $a$ is the first term, $d$ the common difference and $a_n$ the $n$th term of the AP: (ii) $a=–18, d=..., n=10, a_n=0$

Solution :

Given:

The first term of the Arithmetic Progression (AP), $a = -18$.

The number of terms, $n = 10$.

The $n$th term of the AP, $a_n = 0$.

To Find:

The common difference, $d$.

Step 1: Stating the General Formula for an Arithmetic Progression

The $n$th term of an Arithmetic Progression is given by the formula:

$a_n = a + (n - 1)d$

[Where $a_n$ is the $n$th term, $a$ is the first term, $n$ is the number of terms, and $d$ is the common difference.]

Step 2: Substituting the Given Values into the Formula

Substitute $a = -18$, $n = 10$, and $a_n = 0$ into the equation:

$0 = -18 + (10 - 1)d$

Step 3: Simplifying the Expression

Perform the subtraction inside the parentheses:

$0 = -18 + (9)d$

$0 = -18 + 9d$

Step 4: Isolating the Variable $d$

Add $18$ to both sides of the equation to isolate the term containing $d$:

$0 + 18 = 9d$

$18 = 9d$

Divide both sides by $9$ to solve for $d$:

$d = \frac{18}{9}$

$d = 2$

[Since $18 \div 9 = 2$]

Final Answer: The common difference $d$ is 2.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.2


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


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