Brookefield, Bangalore 
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Sister nivedita university (techno india), newtown Pursuing
Bachelor of Technology (B.Tech.)
Brookefield, Bangalore, India - 560037
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Class Location
Online class via Zoom
Student's Home
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Years of Experience in Class 10 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Physics, Computer Application, Science, Chemistry, Social Science, Mathematics, Biology, Bengali, EVS, Computer Practices, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
3
Fees
₹ 500.0 per hour
Board
ICSE, CBSE
Subjects taught
Social studies, Computers, Computer Science, EVS, Mathematics, Bengali, Science
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Mathematics, Computer Science, Bengali, Computers, Science, Physics, Biology, English, EVS, Chemistry
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Social science, Chemistry, Bengali, Physics, Mathematics, Computer Science, Science, Computers, English, Biology, EVS
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Social science, Chemistry, Computer Science, English, Science, Biology, EVS, Computers, Bengali, Mathematics, Physics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Chemistry, Social Science, Computer Application, Physics, Biology, Science, English, Bengali, Computer Practices, Mathematics, EVS
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
State
Subjects taught
Bengali, Computer Science, Mathematics, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
State
Subjects taught
English, Mathematics, Computer Science, Bengali
Taught in School or College
No
Answered on 16/10/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
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If the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
If the capacitors are connected in parallel then equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
Like 0 
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Physics, Computer Application, Science, Chemistry, Social Science, Mathematics, Biology, Bengali, EVS, Computer Practices, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
3
Fees
₹ 500.0 per hour
Board
ICSE, CBSE
Subjects taught
Social studies, Computers, Computer Science, EVS, Mathematics, Bengali, Science
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Mathematics, Computer Science, Bengali, Computers, Science, Physics, Biology, English, EVS, Chemistry
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Social science, Chemistry, Bengali, Physics, Mathematics, Computer Science, Science, Computers, English, Biology, EVS
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Social science, Chemistry, Computer Science, English, Science, Biology, EVS, Computers, Bengali, Mathematics, Physics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
State, CBSE, ICSE
Subjects taught
Chemistry, Social Science, Computer Application, Physics, Biology, Science, English, Bengali, Computer Practices, Mathematics, EVS
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
State
Subjects taught
Bengali, Computer Science, Mathematics, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
State
Subjects taught
English, Mathematics, Computer Science, Bengali
Taught in School or College
No
Answered on 16/10/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
Ask a Question
Post a Lesson
If the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
If the capacitors are connected in parallel then equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
Like 0 Answers 7 Comments Ask a Question
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