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BTech Tuition > BTech Tuition in Bangalore > BTech Tuition in Bannerghatta Main Road > Nagaraj Km

Nagaraj Km BTech Tuition trainer in Bangalore

Nagaraj Km

locationImg Bannerghatta Main Road, Bangalore
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Civil Engineer

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Tutor's home
I'm a civil engineer. If tutoring needed in my domain, I'm ready to do it with little flexiblity in time. I'm working in one of the reputed Construction company of India. I can assure you that I'll use my practical knowledge to teach the best any one needed it.

Languages Spoken

English

Kannada

Hindi

Education

Visvesvaraya Technological University 2015

Bachelor of Engineering (B.E.)

Address

Bannerghatta Main Road, Bangalore, India - 560076

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Teaches

BTech Tuition

Class Location

Online class via Zoom

Student's Home

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BTech Branch

BTech Civil Engineering

Taught in School or College

Yes

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Answers by Nagaraj Km

Answered on 25/12/2015

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Give me a simple bar bending schedule of slab.

Consider a slab, square in shape with dimension of 3000*3000mm and steel datail is given as 8mm rods 125c/c. Then you have to calculate the number of bars, i.e., 3000/125 = 24 bars of 8mm in both the direction. So you have to cut down 24+24 = 48 bars of 3000mm. So the weight of 8mm bar per metre length... ...more
Consider a slab, square in shape with dimension of 3000*3000mm and steel datail is given as 8mm rods 125c/c. Then you have to calculate the number of bars, i.e., 3000/125 = 24 bars of 8mm in both the direction. So you have to cut down 24+24 = 48 bars of 3000mm. So the weight of 8mm bar per metre length is 0.3968kg. Total weigth of the steel is given by 0.3968*48*3 = 57.1392. So that's rounded off to 57.14kg of steel you require. This is one simple example for slab BBS. So I think I answered properly to your query.
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Teaches

BTech Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BTech Branch

BTech Civil Engineering

Taught in School or College

Yes

No Reviews yet!

Answers by Nagaraj Km

Answered on 25/12/2015

Ask a Question

Post a Lesson

Give me a simple bar bending schedule of slab.

Consider a slab, square in shape with dimension of 3000*3000mm and steel datail is given as 8mm rods 125c/c. Then you have to calculate the number of bars, i.e., 3000/125 = 24 bars of 8mm in both the direction. So you have to cut down 24+24 = 48 bars of 3000mm. So the weight of 8mm bar per metre length... ...more
Consider a slab, square in shape with dimension of 3000*3000mm and steel datail is given as 8mm rods 125c/c. Then you have to calculate the number of bars, i.e., 3000/125 = 24 bars of 8mm in both the direction. So you have to cut down 24+24 = 48 bars of 3000mm. So the weight of 8mm bar per metre length is 0.3968kg. Total weigth of the steel is given by 0.3968*48*3 = 57.1392. So that's rounded off to 57.14kg of steel you require. This is one simple example for slab BBS. So I think I answered properly to your query.
Answers 8 Comments
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