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Q9:
Shazli took a wire of length $44$ cm and bent it into the shape of a circle. Find the radius of that circle. Also find its area. If the same wire is bent into the shape of a square, what will be the length of each of its sides? Which figure encloses more area, the circle or the square? (Take $\pi = \frac{22}{7}$)
Solution :
Given Variables & Initial Setup
We are given a single continuous wire of a fixed length that is bent into two different geometric shapes (a circle and a square) in separate scenarios. The fundamental principle governing this problem is the Conservation of Perimeter, which states that the total boundary length of any shape formed by the wire must equal the total length of the wire.
- Total length of the wire, $L = 44 \text{ cm}$
- Mathematical constant, $\pi = \frac{22}{7}$
Step 1: Analyzing the Circular Shape and Finding the Radius
When the wire is bent into the shape of a circle, the entire length of the wire forms the boundary of the circle. [Per the geometric definition of circumference, the perimeter of a circle is its circumference].
Let $r$ be the radius of the circle. The formula for the circumference $C$ is:
$C = 2\pi r$
Equating the circumference to the total length of the wire:
$2\pi r = 44$
Substituting the given value of $\pi$:
$2 \left( \frac{22}{7} \right) r = 44$
$\frac{44}{7} r = 44$
Isolating $r$ by multiplying both sides by $\frac{7}{44}$:
$r = 44 \times \frac{7}{44}$
$r = 7 \text{ cm}$
Step 2: Calculating the Area of the Circle
The area $A_{circle}$ enclosed by a circle is given by the formula:
$A_{circle} = \pi r^2$
Substituting $r = 7 \text{ cm}$ and $\pi = \frac{22}{7}$:
$A_{circle} = \frac{22}{7} \times (7)^2$
$A_{circle} = \frac{22}{7} \times 49$
$A_{circle} = 22 \times 7$
$A_{circle} = 154 \text{ cm}^2$
Step 3: Analyzing the Square Shape and Finding the Side Length
When the same wire is bent into the shape of a square, the total length of the wire forms the perimeter of the square. [Per the properties of regular polygons, a square has four sides of equal length].
Let $s$ be the side length of the square. The formula for the perimeter $P$ of a square is:
$P = 4s$
Equating the perimeter to the total length of the wire:
$4s = 44$
Isolating $s$ by dividing both sides by $4$:
$s = \frac{44}{4}$
$s = 11 \text{ cm}$
Step 4: Calculating the Area of the Square
The area $A_{square}$ enclosed by a square is given by the formula:
$A_{square} = s^2$
Substituting $s = 11 \text{ cm}$:
$A_{square} = (11)^2$
$A_{square} = 121 \text{ cm}^2$
Step 5: Visualizing and Comparing the Enclosed Areas
We now compare the calculated areas to determine which geometric figure maximizes the enclosed space for a given perimeter (an application of the Isoperimetric Inequality).
- Area of the Circle: $154 \text{ cm}^2$
- Area of the Square: $121 \text{ cm}^2$
Since $154 \text{ cm}^2 > 121 \text{ cm}^2$, the circle encloses a significantly larger area than the square.
Final Solution: The radius of the circle is $7 \text{ cm}$ and its area is $154 \text{ cm}^2$. When bent into a square, the length of each side is $11 \text{ cm}$ and its area is $121 \text{ cm}^2$. Comparing the two, the circle encloses more area than the square.
More Questions from Class 9 Mathematics Coordinate Geometry EXERCISE 9.2
- Q1(a): Find the circumference of the circles with the following radius: (Take $\pi = \frac{22}{7}$) (a) $14$ cm
- Q1(b): Find the circumference of the circles with the following radius: (Take $\pi = \frac{22}{7}$) (b) $28$ mm
- Q1(c): Find the circumference of the circles with the following radius: (Take $\pi = \frac{22}{7}$) (c) $21$ cm
- Q10: From a circular card sheet of radius $14$ cm, two circles of radius $3.5$ cm and a rectangle of length $3$ cm and breadth $1$cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take $\pi = \frac{22}{7}$)
- Q11: A circle of radius $2$ cm is cut out from a square piece of an aluminium sheet of side $6$ cm. What is the area of the left over aluminium sheet? (Take $\pi = 3.14$)
- Q12: The circumference of a circle is $31.4$ cm. Find the radius and the area of the circle? (Take $\pi = 3.14$)
- Q13: A circular flower bed is surrounded by a path $4$ m wide. The diameter of the flower bed is $66$ m. What is the area of this path? ($\pi = 3.14$)
- Q14: A circular flower garden has an area of $314$ m$^2$. A sprinkler at the centre of the garden can cover an area that has a radius of $12$ m. Will the sprinkler water the entire garden? (Take $\pi = 3.14$)
- Q15: Find the circumference of the inner and the outer circles, shown in the adjoining figure? (Take $\pi = 3.14$)
- Q16: How many times a wheel of radius $28$ cm must rotate to go $352$ m? (Take $\pi = \frac{22}{7}$)
- Q17: The minute hand of a circular clock is $15$ cm long. How far does the tip of the minute hand move in $1$ hour. (Take $\pi = 3.14$)
- Q2(a): Find the area of the following circles, given that: (a) radius = $14$ mm (Take $\pi = \frac{22}{7}$)
- Q2(b): Find the area of the following circles, given that: (b) diameter = $49$ m
- Q2(c): Find the area of the following circles, given that: (c) radius = $5$ cm
- Q3: If the circumference of a circular sheet is $154$ m, find its radius. Also find the area of the sheet. (Take $\pi = \frac{22}{7}$)
- Q4: A gardener wants to fence a circular garden of diameter $21$ m. Find the length of the rope he needs to purchase, if he makes $2$ rounds of fence. Also find the cost of the rope, if it costs ₹ $4$ per meter. (Take $\pi = \frac{22}{7}$)
- Q5: From a circular sheet of radius $4$ cm, a circle of radius $3$ cm is removed. Find the area of the remaining sheet. (Take $\pi = 3.14$)
- Q6: Saima wants to put a lace on the edge of a circular table cover of diameter $1.5$ m. Find the length of the lace required and also find its cost if one meter of the lace costs ₹ $15$. (Take $\pi = 3.14$)
- Q7: Find the perimeter of the adjoining figure, which is a semicircle including its diameter.
- Q8: Find the cost of polishing a circular table-top of diameter $1.6$ m, if the rate of polishing is ₹ $15/m^2$. (Take $\pi = 3.14$)
CBSE Solutions for Class 9 Mathematics Coordinate Geometry
Chapters in CBSE - Class 9 Mathematics
Top Tutors who teach Coordinate Geometry
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